46.5 g of nickel(II) sulfate hexahydrate, a common allergen in patch tests, is heated in an oven until all the water is driven off. What is the mass of the anhydrous compound?

The subject of this question is to find the mass of anhydrous nickel(II) sulfate after the removal of water from nickel(ii) sulfate hexahydrate. First, we need to know the molar masses of the components of the hexahydrate compound. The molar mass of nickel(II) sulfate (NiSO4) is approximately 154.75 g/mol. And the molar mass of water (H2O) in the hexahydrate is 6*18.015 g/mol = 108.09 g/mol. So, the total molar mass of nickel(II) sulfate hexahydrate (NiSO4.6H2O) is 154.75 g/mol + 108.09 g/mol = 262.84 g/mol. Then, we calculate the mass fraction of NiSO4 in the hexahydrate, which is 154.75 g/mol / 262.84 g/mol = 0.589. Finally, we multiply the weight of the initial sample by this fraction to find the mass of anhydrous NiSO4: 46.5 g * 0.589 = 27.4 g. So, the mass of the anhydrous compound is around 27.4 g.

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