High School

A woman opens a 1.10 m wide door by pushing on it with a force of 46.5 N applied at the center of the door, at an angle perpendicular to the door's surface. What is the magnitude of the torque (in N⋅m)?

Answer :

Final answer:

Given the force is applied perpendicular to the door, the angle is 90 degrees, the magnitude of torque exerted on the door is 51.15 N⋅m.

Explanation:

The magnitude of the torque can be found by using the formula for torque, which is

Torque = Force x Distance x sin θ,

where θ is the angle formed between the direction of the force and the direction of the distance (from the point of the application of the force to the axis of rotation).

In this case, the force is perpendicular to the door, so the angle θ is 90 degrees. The sin 90 degrees is 1.

So, the calculation of the torque would be

Torque = 46.5 N * 1.10 m * sin 90°

= 46.5 N * 1.10 m * 1

= 51.15 N⋅m.

Therefore, the magnitude of the torque applied to the door is 51.15 N⋅m.

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