Answer :
ANSWER:
[tex](\frac{1}{2},\infty)[/tex]
EXPLANATION:
Remember that any logarithm is capable of recieveng numbers that are greater than zero. This way, we'll have the restriction:
[tex]2x-1>0[/tex]Solving for x,
[tex]\begin{gathered} 2x-1>0 \\ \rightarrow2x>1 \\ \\ \Rightarrow x>\frac{1}{2} \end{gathered}[/tex]This way, the domain is:
[tex](\frac{1}{2},\infty)[/tex]