Answer :
The percent yield for the reaction between 46.5 g of ZnS and 13.3 g of oxygen if 18.4 g of ZnO is recovered along with an unknown quantity of sulfur dioxide is 47.39%.
What is percent yield?
Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.
In the given reaction, 194.94 g ZnS gives 162.76 g ZnO, thus 46.5 g ZnS gives 46.5×162.76/194.94=38.82 g which is theoretical yield, and observed yield is 18.4 g.
Thus percent yield, 18.4/38.82×100=47.39%.
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