Answer :
46.74% of the reaction's yield was expressed as a percentage.
The percentage yield can be expressed as the difference between the theoretical yield and the actual yield.
The chemical equation for a balanced system states that 2 moles 2 moles of ZnO ZnS 0.222 mol ZnO equals 0.222 mol ZnS 2 mol ZnO equals 3 mol Oxygen
0.222 mol ZnO Equals 0.334 mol of oxygen
The percentage yield can be computed using any of the reactants because both reactants are present in sufficient concentration. Theoretically, 46.5 grams of ZnS would yield 1 mole of ZnO, or 0.477 moles of ZnS would yield 0.477 moles of ZnO.
0.477 mol of ZnO weighs:
Molecular weight equals mass in moles
ZnO mass = 0.477 81.38
ZnO has a mass of 38.818 grams.
ZnO has a 38.818 g theoretical yield.
18.14 g of ZnO were really produced.
Yield percentage equals 18.14/38.81 x 100.
Yield as a percentage is 46.74%.
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