High School

Evaluate the logarithmic function using properties of logarithmic functions. Discuss

which property or properties would be used to evaluate.

log5 230 = x

Evaluate the logarithmic function using properties of logarithmic functions Discuss which property or properties would be used to evaluate log5 230 x

Answer :

Final answer:

To evaluate the logarithmic function log5 230 = x, apply the property that the logarithm of a number raised to an exponent is the product of the exponent and the logarithm of the number. By rewriting the equation and simplifying, x is found to be equal to 1.

Explanation:

To evaluate the logarithmic function log5 230 = x, we can use the property of logarithms that states: the logarithm of a number raised to an exponent is the product of the exponent and the logarithm of the number. In this case, we can rewrite 230 as 5 raised to some power:

230 = 5x

Now we can take the logarithm of both sides using base 5:

log5 230 = log5 (5x)

By the property mentioned earlier, we can rewrite the right-hand side as:

x * log5 5

Since log5 5 = 1, we have:

x * 1

Therefore, the value of x is simply equal to:

x = 1

The value of x in the given logarithmic function is: x = 3.379

How to identify properties of logarithm?

There are different properties of Logarithm such as:

Product property

Quotient property

Power property

Change of base property

From properties of logarithm, we know that:

If logₐ m = x

Then: m = aˣ

Thus:

log₅230 = x gives us:

5ˣ = 230

x In 5 = In 230

x = 3.379

Read more about Properties of Logarithm at: https://brainly.com/question/12049968

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