Answer :
Let's work through each of the given questions step by step.
### Question 1:
We are given the function:
[tex]\[ f(x) = 4|x-5| + 3 \][/tex]
We need to find the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 15 \)[/tex]. So we set up the equation:
[tex]\[ 4|x-5| + 3 = 15 \][/tex]
1. Subtract 3 from both sides:
[tex]\[ 4|x-5| = 12 \][/tex]
2. Divide both sides by 4:
[tex]\[ |x-5| = 3 \][/tex]
3. Solve the absolute value equation. This means we solve the two equations:
- [tex]\( x - 5 = 3 \)[/tex]
- [tex]\( x - 5 = -3 \)[/tex]
4. Solve each equation:
- [tex]\( x - 5 = 3 \)[/tex] → [tex]\( x = 8 \)[/tex]
- [tex]\( x - 5 = -3 \)[/tex] → [tex]\( x = 2 \)[/tex]
So, the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 15 \)[/tex] are [tex]\( x = 2 \)[/tex] and [tex]\( x = 8 \)[/tex].
### Question 2:
We are given the function:
[tex]\[ f(x) = -0.5|2x + 2| + 1 \][/tex]
We need to find the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 6 \)[/tex]. So we set up the equation:
[tex]\[ -0.5|2x + 2| + 1 = 6 \][/tex]
1. Subtract 1 from both sides:
[tex]\[ -0.5|2x + 2| = 5 \][/tex]
2. Divide both sides by -0.5:
[tex]\[ |2x + 2| = -10 \][/tex]
An absolute value cannot equal a negative number. Therefore, there is no solution for [tex]\( x \)[/tex] that satisfies the equation [tex]\( f(x) = 6 \)[/tex].
So, for the second function, the solution is "no solution."
### Question 1:
We are given the function:
[tex]\[ f(x) = 4|x-5| + 3 \][/tex]
We need to find the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 15 \)[/tex]. So we set up the equation:
[tex]\[ 4|x-5| + 3 = 15 \][/tex]
1. Subtract 3 from both sides:
[tex]\[ 4|x-5| = 12 \][/tex]
2. Divide both sides by 4:
[tex]\[ |x-5| = 3 \][/tex]
3. Solve the absolute value equation. This means we solve the two equations:
- [tex]\( x - 5 = 3 \)[/tex]
- [tex]\( x - 5 = -3 \)[/tex]
4. Solve each equation:
- [tex]\( x - 5 = 3 \)[/tex] → [tex]\( x = 8 \)[/tex]
- [tex]\( x - 5 = -3 \)[/tex] → [tex]\( x = 2 \)[/tex]
So, the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 15 \)[/tex] are [tex]\( x = 2 \)[/tex] and [tex]\( x = 8 \)[/tex].
### Question 2:
We are given the function:
[tex]\[ f(x) = -0.5|2x + 2| + 1 \][/tex]
We need to find the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 6 \)[/tex]. So we set up the equation:
[tex]\[ -0.5|2x + 2| + 1 = 6 \][/tex]
1. Subtract 1 from both sides:
[tex]\[ -0.5|2x + 2| = 5 \][/tex]
2. Divide both sides by -0.5:
[tex]\[ |2x + 2| = -10 \][/tex]
An absolute value cannot equal a negative number. Therefore, there is no solution for [tex]\( x \)[/tex] that satisfies the equation [tex]\( f(x) = 6 \)[/tex].
So, for the second function, the solution is "no solution."