Answer :
Final answer:
Approximately 1295.5 kJ of heat is needed to raise the temperature of 14000 g of liquid water from 24.4 °C to 46.5 °C.
Explanation:
The subject matter of the student's question is associated with thermal physics, which involves the calculation of heat transfer. To identify the amount of heat necessary to change the temperature of a particular mass of water from one temperature to another, the equation q=mcΔT can be used, where 'q' is the heat energy, 'm' is the mass, 'c' is the specific heat capacity, and 'ΔT' is the change in temperature.In this case, the mass (m) of the water is 14000 g, the specific heat capacity (c) of liquid water is 4.184 J/g °C, and the change in temperature (ΔT) is (46.5-24.4) °C = 22.1 °C. Thus, the equation becomes: q = (14000 g) x (4.184 J/g °C) x (22.1 °C) = 1295485.6 Joules. But since we want the answer in kJ, we have to divide by 1000, so q ≈ 1295.5 kJ.
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