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How many moles of [tex]HNO_3[/tex] will be produced from the reaction of 46.5 g of [tex]NO_2[/tex] with excess water in the following chemical reaction?

\[ 3 NO_2(g) + H_2O (l) \rightarrow 2 HNO_3(g) + NO(g) \]

Answer :

Final answer:

To determine the moles of HNO3 produced, you need to convert the given mass of NO2 to moles and use the mole ratio from the balanced equation.

Explanation:

To find the number of moles of HNO3 produced, you need to convert the given mass of NO2 to moles using its molar mass. The molar mass of NO2 is 46 g/mol. Divide the given mass by the molar mass to get the moles of NO2. In this case, 46.5 g NO2 / 46 g/mol = 1 mole of NO2. According to the balanced equation, 3 moles of NO2 produce 2 moles of HNO3. Therefore, 1 mole of NO2 will produce (2/3) moles of HNO3.

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Answer:

0.674 moles HNO₃

Explanation:

To find the moles of HNO₃, you need to (1) convert grams NO₂ to moles NO₂ (via molar mass) and then (2) convert moles NO₂ to moles HNO₃ (via mole-to-mole ratio from equation coefficients). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (46.5 g).

Molar Mass (NO₂): 14.007 g/mol + 2(15.998 g/mol)

Molar Mass (NO₂): 46.003 g/mol

3 NO₂(g) + H₂O (l) ------> 2 HNO₃(g) + NO(g)

46.5 g NO₂ 1 mole 2 moles HNO₃
------------------- x ------------------- x -------------------------- = 0.674 moles HNO
46.003 g 3 moles NO₂