Answer :
The required solution for the given arithmetic problems are,
A) 2/5
B) 72 / 125
C) 6, 3/4, 12/5, and 3/10
D) 4, 1/6 and 6
A) 12/25 times 15/18.
Division of two fractions performed as multiplication of numerator of one fraction with a denominator of another function over a denominator of one function with a numerator of another function.
= 12 / 25 * 15 / 18 = 2 / 5
Similarly
b) 12/25 divided by 15/18.
= [12 / 25 ] / 15 / 18
= 12 / 25 * 18 / 15
= 72 / 125
C) 6 and 3/4 times 1 and 2/5
6 * 1 = 6
3 / 4 * 1 = 3/4
6 * 2/5 = 12/5
3/4 * 2/5 = 3 / 10
D) 4 and 1/6 divided by 1 and 2/3.
= 4 / 1 = 4
= 1/6 / 1 = 1/6
= 4 / 2/3 = 6
= 1/6 / 2/3 = 1/4
Thus, the required solution for the given arithmetic problems is mentioned above.
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