High School

Over a period of 2.50 seconds, a speedboat accelerates uniformly from 18.5 m/s to 46.5 m/s. What is the acceleration of the speedboat relative to the shore?

Answer :

According to the question, the acceleration of the speedboat relative to the shore is found to be 11.2 [tex]m/sec^2.[/tex]

What is Acceleration?

Acceleration may be characterized as the rate of change of the velocity of an object with respect to time. It is a vector quantity, as it defined both magnitude and direction. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

According to the question,

The initial velocity of the boat = 18.5 m/s.

The final velocity of the boat = 46.5 m/s.

Difference in velocity = Final velocity - Initial velocity = 46.5-18.5 = 28 m/s.

The formula for calculating the acceleration of the boat is as follows:

  • a = Difference in velocity/time taken.

= 28/2.50 = 11.2 [tex]m/sec^2[/tex].

Therefore, the acceleration of the speedboat relative to the shore is found to be 11.2 [tex]m/sec^2.[/tex]

To learn more about Acceleration, refer to the link:

https://brainly.com/question/460763

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The answer is : 11.2 m/s2