Razor Razor
  • 04-03-2025
  • Mathematics
High School

Solve 2log₅ (√x) - log₅ (6x-1) = 0.
a. X = 1/6
b. X = 1/5
c. X = 5
d. X = 6

Answer :

olumideolawoyin olumideolawoyin
  • 11-04-2024

Answer:

b. X = 1/5

Step-by-step explanation:

2log₅ (√x) - log₅ (6x-1) = 0.

Apply power law of logarithms

log₅ (√x)² - log₅ (6x-1) = 0

log₅ x - log₅ (6x-1) = 0

Apply division law of logarithms

[tex] log_{5} (\frac{x}{6x - 1})= 0[/tex]

[tex] \frac{x}{6x - 1} = {5}^{0} = 1[/tex]

x = 6x - 1

6x - x = 1

5x = 1 Divide both sides by 5

x = 1/5

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