Answer :
Final answer:
To find the proportion of babies shorter than 46.5 cm in a normally distributed population with a mean of 50 cm and a standard deviation of 3.5 cm, we can use the Z-score formula. The proportion is approximately 0.1587.
Explanation:
To solve this problem, we can use the Z-score formula: Z = (X - μ) / σ, where X is the value we want to find the proportion for, μ is the mean, and σ is the standard deviation.
Plugging in the values from the question, we get: Z = (46.5 - 50) / 3.5 = -1
To find the proportion of babies shorter than 46.5 cm, we need to find the area to the left of Z = -1 on a standard normal distribution table.
Based on the table, the proportion is approximately 0.1587.