Answer :
To solve this problem, we want to find the sum of the fractions [tex]\(\frac{7}{12}\)[/tex] and [tex]\(\frac{18}{12}\)[/tex].
1. Add the Fractions:
- Since both fractions have the same denominator (12), we can directly add the numerators.
- The sum of the numerators is [tex]\(7 + 18 = 25\)[/tex].
2. Write the Result as a Single Fraction:
- Combine the sum of the numerators over the common denominator:
[tex]\[
\frac{25}{12}
\][/tex]
3. Convert the Improper Fraction to a Mixed Number:
- Divide the numerator by the denominator to find how many whole parts there are:
[tex]\[
25 \div 12 = 2 \text{ remainder } 1
\][/tex]
- Thus, the mixed number is [tex]\(2\)[/tex] with a remainder of [tex]\(1\)[/tex], which can be written as a mixed number:
[tex]\[
2 \frac{1}{12}
\][/tex]
The sum of [tex]\(\frac{7}{12}\)[/tex] and [tex]\(\frac{18}{12}\)[/tex] is [tex]\(2 \frac{1}{12}\)[/tex]. Therefore, the correct answer is B. [tex]\(2 \frac{1}{12}\)[/tex].
1. Add the Fractions:
- Since both fractions have the same denominator (12), we can directly add the numerators.
- The sum of the numerators is [tex]\(7 + 18 = 25\)[/tex].
2. Write the Result as a Single Fraction:
- Combine the sum of the numerators over the common denominator:
[tex]\[
\frac{25}{12}
\][/tex]
3. Convert the Improper Fraction to a Mixed Number:
- Divide the numerator by the denominator to find how many whole parts there are:
[tex]\[
25 \div 12 = 2 \text{ remainder } 1
\][/tex]
- Thus, the mixed number is [tex]\(2\)[/tex] with a remainder of [tex]\(1\)[/tex], which can be written as a mixed number:
[tex]\[
2 \frac{1}{12}
\][/tex]
The sum of [tex]\(\frac{7}{12}\)[/tex] and [tex]\(\frac{18}{12}\)[/tex] is [tex]\(2 \frac{1}{12}\)[/tex]. Therefore, the correct answer is B. [tex]\(2 \frac{1}{12}\)[/tex].