Answer :
Let's solve each of the given fractions step-by-step.
[tex]\frac{12}{25} + \frac{18}{25}[/tex]
Since the fractions have the same denominator, you can simply add the numerators:
[tex]\frac{12 + 18}{25} = \frac{30}{25}[/tex]
Simplifying [tex]\frac{30}{25}[/tex]:
[tex]\frac{30}{25} = \frac{6}{5}[/tex]
[tex]\frac{27}{40} - \frac{9}{32}[/tex]
First, find the least common denominator (LCD) of 40 and 32. The LCD is 160.
Convert each fraction to have a denominator of 160:
[tex]\frac{27}{40} = \frac{27 \times 4}{40 \times 4} = \frac{108}{160}[/tex]
[tex]\frac{9}{32} = \frac{9 \times 5}{32 \times 5} = \frac{45}{160}[/tex]
Now subtract the fractions:
[tex]\frac{108}{160} - \frac{45}{160} = \frac{63}{160}[/tex]
[tex]\frac{12}{25} + \frac{7}{20}[/tex]
Find the least common denominator (LCD) of 25 and 20. The LCD is 100.
Convert each fraction:
[tex]\frac{12}{25} = \frac{12 \times 4}{25 \times 4} = \frac{48}{100}[/tex]
[tex]\frac{7}{20} = \frac{7 \times 5}{20 \times 5} = \frac{35}{100}[/tex]
Add the fractions:
[tex]\frac{48}{100} + \frac{35}{100} = \frac{83}{100}[/tex]
[tex]\frac{48}{60} - \frac{33}{60}[/tex]
Since the fractions have the same denominator, subtract the numerators:
[tex]\frac{48 - 33}{60} = \frac{15}{60}[/tex]
Simplify [tex]\frac{15}{60}[/tex]:
[tex]\frac{15}{60} = \frac{1}{4}[/tex]
[tex]\frac{14}{35} + \frac{6}{21}[/tex]
Find the least common denominator (LCD) of 35 and 21. The LCD is 105.
Convert each fraction:
[tex]\frac{14}{35} = \frac{14 \times 3}{35 \times 3} = \frac{42}{105}[/tex]
[tex]\frac{6}{21} = \frac{6 \times 5}{21 \times 5} = \frac{30}{105}[/tex]
Add the fractions:
[tex]\frac{42}{105} + \frac{30}{105} = \frac{72}{105}[/tex]
Simplify [tex]\frac{72}{105}[/tex]:
[tex]\frac{72}{105} = \frac{24}{35}[/tex]
[tex]\frac{9}{16} - \frac{5}{24}[/tex]
Find the least common denominator (LCD) of 16 and 24. The LCD is 48.
Convert each fraction:
[tex]\frac{9}{16} = \frac{9 \times 3}{16 \times 3} = \frac{27}{48}[/tex]
[tex]\frac{5}{24} = \frac{5 \times 2}{24 \times 2} = \frac{10}{48}[/tex]
Subtract the fractions:
[tex]\frac{27}{48} - \frac{10}{48} = \frac{17}{48}[/tex]
I hope this step-by-step breakdown helps you understand how to solve these fraction problems!