Answer :
Final answer:
The inductance of the coiled telephone cord can be determined using the formula for the inductance of a solenoid. The specifics of the cord, such as it having 69.0 turns, a diameter of 1.30 cm, and an unstretched length of 46.5 cm, can be plugged into this formula to find the inductance.
Explanation:
The important concept here is inductance, which is essentially the ability of a conductor to store energy in a magnetic field. In a coiled telephone cord, this concept is relevant due to the helical or spiral shape of the wire. This configuration maximizes the potential for inductance.
When we have a coiled wire forming a spiral with 69.0 turns having a diameter of 1.30 cm, we can calculate the inductance of one conductor when the cord is unstretched having a total length of 46.5 cm by considering the properties of a solenoid. A solenoid is a coil of wire in the shape of a tightly wound helix, which is what we have in a coiled telephone cord.
The formula to calculate inductance (L) of a solenoid is: L = µₒ * (N²*a)/l, where N is number of turns, a is the cross-sectional area of the coil, l is the length of the coil, and μₒ denotes the permeability of free space (approximately 4π x 10^-7 H/m). The cross-sectional area can be calculated as a = π*(d/2)², where d is the diameter of the cord.
By substituting the given values in our case, i.e. N = 69, a = π*(1.3 cm/2)², l = 46.5 cm, we can find the inductance of the cord.
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