If log5=b, what is log1250 in terms of B

The log 1250 in base 5 would be 4.43067655807.
When you raise a number with an exponent, there comes a result.
Lets say you get a^b = c
Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows
[tex]b = \log_a(c)[/tex]'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'
Given that log 5 in base 10=b, then we need to find the log 1250 in base 5 in term of b.
Log(1250) base 5 = Log(1250) ÷ Log(5)
Log(1250) = 3.09691001301
Log(5)=0.698970004336
Log(1250) base 5=3.09691001301 ÷ 0.698970004336
Log(1250) base 5= 4.43067655807
Hence, the the log 1250 in base 5 would be 4.43067655807.
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