High School

In a random sample of 1600 people from a large city, it is found that 896 support the incumbent mayor in the upcoming election. Based on this sample, and with a [tex]95\%[/tex] confidence level, estimate the proportion of the population that supports the incumbent mayor.

Answer :

Based on a random sample, we can estimate the proportion of people in the city who support the incumbent mayor with 95% confidence.

To estimate the proportion of people in the city who support the incumbent mayor, we can use a confidence interval. The formula for calculating the confidence interval for a proportion is given by:

[tex]\[ \text{{Confidence Interval}} = \hat{p} \pm z \cdot \sqrt{\frac{\hat{p} \cdot (1 - \hat{p})}{n}} \][/tex]

where [tex]\(\hat{p}\)[/tex] is the sample proportion, z is the critical value based on the desired confidence level (95% in this case), and n is the sample size.

In this scenario, the sample proportion is [tex]\(\frac{896}{1600} = 0.56\)[/tex]. Since we want a 95% confidence level, the critical value z can be obtained from a standard normal distribution table or a statistical software and is approximately 1.96 for a large sample size.

Calculating the confidence interval:

[tex]\[ \text{{Confidence Interval}} = 0.56 \pm 1.96 \cdot \sqrt{\frac{0.56 \cdot (1 - 0.56)}{1600}} \][/tex]

Simplifying the expression gives us the confidence interval for the proportion of people in the city who support the incumbent mayor.

Learn more about confidence here:

https://brainly.com/question/30265803

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