Answer :
Final answer:
Three molecules of CO₂ combine in the Calvin Cycle to form one molecule of G3P, which exits the cycle to help form glucose. The correct answer is d. G3P.
Explanation:
When three molecules of CO₂ enter the Calvin Cycle, they are recombined to form one molecule of G3P (Glyceraldehyde-3-Phosphate). That molecule will then exit the cycle to be utilized in the formation of glucose. Consequently, the correct answer is d. G3P. Furthermore, one of the G3P molecules leaves the Calvin cycle to contribute to the formation of the carbohydrate molecule, which is commonly glucose (C₆H₁₂0₆). Because the carbohydrate molecule has six carbon atoms, it takes six turns of the Calvin cycle to make one carbohydrate molecule (one for each carbon dioxide molecule fixed). The remaining G3P molecules regenerate RuBP, which enables the system to prepare for the carbon-fixation step. ATP is also used in the regeneration of RuBP.
The molecule that exits the Calvin Cycle to form glucose is d. G3P. One molecule of glucose is formed after six turns of the Calvin Cycle, and during each turn, three molecules of CO₂ are converted into one molecule of G3P. This G3P molecule can then be used to produce glucose.
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