Answer :
The magnitude of the force exerted on the wall, assuming the water's horizontal momentum is reduced to zero is Force = 2049.15 N
To calculate the magnitude of the force exerted on the wall by the water from the fire hose, we need to consider the change in momentum and the rate at which it occurs.
The initial momentum of the water is given by the product of its mass flow rate (44.1 kg/s) and its speed (46.5 m/s). Since the horizontal momentum of the water is reduced to zero upon impact, the change in momentum is equal to the initial momentum.
Now, we can use the impulse-momentum theorem, which states that the force exerted on the wall multiplied by the time it acts is equal to the change in momentum. In this case, the time over which the force acts is 1 second because the mass flow rate is given in kg/s.
So, the force exerted on the wall can be calculated as follows:
Force = (Change in momentum) / Time
Force = (44.1 kg/s * 46.5 m/s) / 1 s
By solving the equation, we find the magnitude of the force exerted on the wall:
Force = 2049.15 N
Thus, the force exerted on the wall by the water from the fire hose is approximately 2049.15 Newtons.
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