College

What is the sum of [tex]$\frac{7}{12}$[/tex] and [tex]$\frac{18}{12}$[/tex]?

A. [tex][tex]$1 \frac{1}{24}$[/tex][/tex]
B. [tex]$2 \frac{1}{12}$[/tex]
C. [tex]$\frac{12}{25}$[/tex]
D. [tex][tex]$\frac{11}{12}$[/tex][/tex]

Answer :

We start with the two fractions:

[tex]$$
\frac{7}{12} \quad \text{and} \quad \frac{18}{12}.
$$[/tex]

Since they have the same denominator, we add the numerators directly:

[tex]$$
\frac{7}{12} + \frac{18}{12} = \frac{7+18}{12} = \frac{25}{12}.
$$[/tex]

Next, we convert the improper fraction [tex]$\frac{25}{12}$[/tex] into a mixed number. To do this, we divide the numerator by the denominator:

[tex]$$
25 \div 12 = 2 \text{ R } 1,
$$[/tex]

which means the integer part is [tex]$2$[/tex] and the remainder is [tex]$1$[/tex]. This gives us:

[tex]$$
\frac{25}{12} = 2\frac{1}{12}.
$$[/tex]

Thus, the sum of the fractions is

[tex]$$
\boxed{2\frac{1}{12}}.
$$[/tex]